wims-modules-es (3.64-1) modules/H2/algebra/oef2x2.es/src/rectangle.oef

Summary

 modules/H2/algebra/oef2x2.es/src/rectangle.oef |   19 ++++++++++---------
 1 file changed, 10 insertions(+), 9 deletions(-)

    
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Patch contents

--- wims-modules-es-3.64.orig/modules/H2/algebra/oef2x2.es/src/rectangle.oef
+++ wims-modules-es-3.64/modules/H2/algebra/oef2x2.es/src/rectangle.oef
@@ -1,4 +1,4 @@
-\title{Rectángulo}
+\title{Rectangle}
 \language{en}
 \range{-5..5}
 \author{XIAO Gang}
@@ -12,17 +12,18 @@
 \integer{x=\y+\diff}
 \integer{peri=2*(\x+\y)}
 
-\statement{Tenemos un rectángulo cuyo perímetro es \peri mm. Sabiendo que 
-la altura mide \diff mm más que la anchura, encontrar ambas longitudes
-(en mm).
+\statement{We have a rectangle whose perimeter is \peri mm. Given that 
+the length is \diff mm longer than the width, find out the length and the
+width (in mm).
 }
 
-\answer{Altura}{\x}{type=default}
-\answer{Anchura}{\y}{type=default}
-\solution{Sea x = altura, y = anchura. Entonces
-tenemos el siguiente sistema: <p><center>
+\answer{Length}{\x}{type=default}
+\answer{Width}{\y}{type=default}
+\solution{Let x = length, y = width. Then
+we have the following system. <p><center>
 	2x + 2y = \peri<br>
 	x - y = \diff
 </center> <p>
-Y la solución de este sistema es x=\x, y=\y.
+And the solution of this system is x=\x, y=\y.
 }
+